Thursday, January 31, 2008

Field Trip

Today I had a wonderful field trip. About 40 kids went on it. The best part is that although we get to leave school and not have any schoolwork, we got to go to ... College! We get to skip school to go to school.
It was like what happened in school once. A kid I knew from last year new someone else in one of my classes. He decided to go to my class instead of his. So he pretended to be "Sven" from out of country. Come on! If your going to skip school don't go across the hall. At least leave the campus.
Well on the field trip we went to a University and a state university they were both good and the food was all you could eat. However we got stuck in traffic on the way home and tossed riddles around.
One riddle was this
An Evil man invites 100 people to his house for a "party". He locks them in and tells them that tomorrow he will line them up facing one person so person 1 can see everyone and person 100 can see no one. He will put white or black hats on their heads and they have to guess right. One person is allowed to get it wrong but if anyone else gets it wrong they all die. They can't move or communicate in any way other then saying the word white or the word black once, also it has to be in a flat tone.
There is a way for this to work and I might post the answer latter.

4 comments:

En-her-gy Girl said...

and WHEN exactly are you going to tell us the answer to the riddle?? It has been driving me nuts since LAST WEEK when you first told us about it.

In the middle of the night, when you hear "AHHHHH!" it's because I'm having nightmares about not being able to solve it. v

AnnaDee said...

he told ME in person. i'd tell YOU but i forgot.....

Vincent Malmrose said...

Sorry already told her... :(

Vincent Malmrose said...

the answer, I believe it has been long enough, is this
The first person says the number of odd hats that he sees. So lets say that there are 67 black hats and 33 white hats. The first person has to have a hat so he can see 66 black and 33 white or 67 black and 32 white. lets assume he sees 66 black and 33 white. The next person however must have a hat so he can see 65 black or 32 white. If he sees two odd numbers, 65 black and 33 white he knows that he has black because he sees everyone that the first person saw except for himself.